(x^2+8)/(x)+1=4(x+2)/x

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Solution for (x^2+8)/(x)+1=4(x+2)/x equation: 



(x^2+8)/(x)+1=4(x+2)/x

We move all terms to the left:

(x^2+8)/(x)+1-(4(x+2)/x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(x^2+8)*x)/x^2+(-(4(x+2)*x)/x^2+1=0

We calculate fractions


((x^2+8)*x)*x^2)/(x^2+(*x^2)+(-(4(x+2)*x)*x^2)/(x^2+(*x^2)+1=0

We get rid of parentheses

((x^2+8)*x)*x^2)/(x^2+*x^2+(-(4(x+2)*x)*x^2)/(x^2+(*x^2)+1=0

We calculate fractions


*x^2+(x^2+((x^2+8)*x)*x^2)*(x^2+1)/((x^2*(x^2+(*x^2)+1)+((-(4(x+2)*x)*x^2)*x^2/((x^2*(x^2+(*x^2)+1)=0



We calculate terms in parentheses: +(x^2+((x^2+8)*x)*x^2)*(x^2+1)/((x^2*(x^2+(*x^2)+1)+((-(4(x+2)*x)*x^2)*x^2/((x^2*(x^2+(*x^2)+1), so:

x^2+((x^2+8)*x)*x^2)*(x^2+1)/((x^2*(x^2+(*x^2)+1)+((-(4(x+2)*x)*x^2)*x^2/((x^2*(x^2+(*x^2)+1

We can not solve this equation

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